document.write( "Question 890789: Train A has a speed 20 miles per hour greater than that of train B. If train A travels 210 miles in the same times train B travels 170 miles, what are the speeds of the two trains? \n" ); document.write( "
Algebra.Com's Answer #539257 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r)times Time(t)or d=rt;r=d/t and t=d/r
\n" ); document.write( "Let r=train B's speed
\n" ); document.write( "Then r+20=train A's speed
\n" ); document.write( "Time required for train A to travel 210 mi=210/(r+20)
\n" ); document.write( "Time required for train B to travel 170 mi=170/r
\n" ); document.write( "Now we are told that these times are equal, so:
\n" ); document.write( "210/(r+20)=170/r divide each term by 10 to simplify
\n" ); document.write( "21/(r+20)=17/r multiply each term by r(r+20)
\n" ); document.write( "21r=17(r+20) expand
\n" ); document.write( "21r=17r+340 subtract 17r from each side
\n" ); document.write( "4r=340
\n" ); document.write( "r=85 mph---Train B's speed
\n" ); document.write( "r+20=85+20=105 mph---train A's speed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "210/105 =170/85
\n" ); document.write( "2=2\r
\n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor
\n" ); document.write( "
\n" );