document.write( "Question 890789: Train A has a speed 20 miles per hour greater than that of train B. If train A travels 210 miles in the same times train B travels 170 miles, what are the speeds of the two trains? \n" ); document.write( "
Algebra.Com's Answer #539257 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Distance(d) equals Rate(r)times Time(t)or d=rt;r=d/t and t=d/r \n" ); document.write( "Let r=train B's speed \n" ); document.write( "Then r+20=train A's speed \n" ); document.write( "Time required for train A to travel 210 mi=210/(r+20) \n" ); document.write( "Time required for train B to travel 170 mi=170/r \n" ); document.write( "Now we are told that these times are equal, so: \n" ); document.write( "210/(r+20)=170/r divide each term by 10 to simplify \n" ); document.write( "21/(r+20)=17/r multiply each term by r(r+20) \n" ); document.write( "21r=17(r+20) expand \n" ); document.write( "21r=17r+340 subtract 17r from each side \n" ); document.write( "4r=340 \n" ); document.write( "r=85 mph---Train B's speed \n" ); document.write( "r+20=85+20=105 mph---train A's speed\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "210/105 =170/85 \n" ); document.write( "2=2\r \n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor \n" ); document.write( " |