document.write( "Question 74963: Solve each of the following problems. Be sure to show the equation used for the solution.\r
\n" ); document.write( "\n" ); document.write( "Geometry. The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle.
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Algebra.Com's Answer #53921 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=Width(W)
\n" ); document.write( "Then 2x+2=Length(L)\r
\n" ); document.write( "\n" ); document.write( "Perimeter(P)=2W+2L so our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "34=2x+2(2x+2) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "34=2x+4x+4 subtract 4 from both sides
\n" ); document.write( "34-4=2x+4x+4-4 collect like terms
\n" ); document.write( "30=6x divide both sides by 6
\n" ); document.write( "x=5 in-------------------------------------width (W)
\n" ); document.write( "2x+2=2*5+2=12 in---------------------------length(L)\r
\n" ); document.write( "\n" ); document.write( "ck\r
\n" ); document.write( "\n" ); document.write( "34=2*5+2*12
\n" ); document.write( "34=34\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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