document.write( "Question 890730: please help me solve : the perimeter of a rectangle is 64 meters. the length is eight meters less than three times the width.
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Algebra.Com's Answer #539201 by josgarithmetic(39617)\"\" \"About 
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VARIABLES: w for width, L for length\r
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\n" ); document.write( "\n" ); document.write( "TRANSLATE: L=-8+3w, 2w+2L=64.\r
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\n" ); document.write( "\n" ); document.write( "SIMPLIFY AND SUBSTITUTE:
\n" ); document.write( "w+L=32;
\n" ); document.write( "w+(3w-8)=32\r
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\n" ); document.write( "\n" ); document.write( "SOLVE FOR w FIRST:
\n" ); document.write( "4w-8=32
\n" ); document.write( "4w=24
\n" ); document.write( "w=6\r
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\n" ); document.write( "\n" ); document.write( "Finish finding L:
\n" ); document.write( "L=3w-8
\n" ); document.write( "L=3*6-8
\n" ); document.write( "L=18-8
\n" ); document.write( "L=10
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