document.write( "Question 890654: A jar containing only nickels and dimes contains a total of 51 coins. The value of all the coins in a jar is $3.80. How many dimes are in the jar!
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Algebra.Com's Answer #539164 by JulietG(1812)\"\" \"About 
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If all 51 coins were dimes, the total would be $5.10
\n" ); document.write( "The actual total is $3.80, a difference of $1.30
\n" ); document.write( "The difference between a nickel and dime is .05
\n" ); document.write( "1.30 / .05 = 26
\n" ); document.write( "26 of the coins are nickels. Therefore, 25 are dimes (51-26)
\n" ); document.write( "26 * .05 = $1.30
\n" ); document.write( "25 * .10 = $2.50
\n" ); document.write( "Total = $3.80
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