document.write( "Question 890654: A jar containing only nickels and dimes contains a total of 51 coins. The value of all the coins in a jar is $3.80. How many dimes are in the jar!
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Algebra.Com's Answer #539164 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! If all 51 coins were dimes, the total would be $5.10 \n" ); document.write( "The actual total is $3.80, a difference of $1.30 \n" ); document.write( "The difference between a nickel and dime is .05 \n" ); document.write( "1.30 / .05 = 26 \n" ); document.write( "26 of the coins are nickels. Therefore, 25 are dimes (51-26) \n" ); document.write( "26 * .05 = $1.30 \n" ); document.write( "25 * .10 = $2.50 \n" ); document.write( "Total = $3.80 \n" ); document.write( " \n" ); document.write( " |