document.write( "Question 890603: 1.Amanda has a piggy bank filled with P1.00- coins. She took out 15 coins less than half the number of coins on Monday. On Tuesday, she took half of the remainder plus 4 coins. She acidentally broke her piggybank on Wednesday and counted there were 12 coins. How many coins were there in the piggybank originally? \n" ); document.write( "
Algebra.Com's Answer #539155 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1.Amanda has a piggy bank filled with P1.00- coins. \n" ); document.write( "let n = original number coins \n" ); document.write( " She took out 15 coins less than half the number of coins on Monday. \n" ); document.write( "n - (.5n-15) \n" ); document.write( "n - .5n + 15 \n" ); document.write( ".5n + 15 remain \n" ); document.write( ": \n" ); document.write( "On Tuesday, she took half of the remainder plus 4 coins. \n" ); document.write( "She accidentally broke her piggy-bank on Wednesday and counted there were 12 coins. \n" ); document.write( "(.5n+15) - (.5(.5n+15)+ 4) = 12 \n" ); document.write( "(.5n+15) - (.25n + 7.5 + 4) = 12 \n" ); document.write( "(.5n+15) - (.25n + 11.5) = 12 \n" ); document.write( ".5n + 15 -.25n - 11.5 = 12 \n" ); document.write( ".5n - .25n + 15 - 11.5 = 12 \n" ); document.write( ".25n + 3.5 = 12 \n" ); document.write( ".25n = 12 - 3.5 \n" ); document.write( ".25n = 8.5 \n" ); document.write( "n = 8.5/.25 \n" ); document.write( "n = 34 coins originally\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |