document.write( "Question 890490: Mr.Cooper invested a sum of money at 6%. He invested a second sum, $150 more than the first, at 3%. If his annual income was $54, how much did he invest at 3%? \n" ); document.write( "

Algebra.Com's Answer #539150 by lwsshak3(11628) $\"\"$ $\"About$

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Mr.Cooper invested a sum of money at 6%. He invested a second sum, $150 more than the first, at 3%. If his annual income was $54, how much did he invest at 3%?
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\n" ); document.write( "let x=sum of money invested at 6%
\n" ); document.write( "x+150=sum of money invested at 3%
\n" ); document.write( "6%x+3%(x+150)=54
\n" ); document.write( ".06x+.03x+4.5=54
\n" ); document.write( ".09x=49.5
\n" ); document.write( "x=550
\n" ); document.write( "x+150=700
\n" ); document.write( "how much did he invest at 3%? $700 \n" ); document.write( "

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