document.write( "Question 890595: Two trains P and Q are traveling from station A to station B at speeds of 100kmph and 120 kmph respectively. Train Q stops at station C for 10 minutes but reaches station B 5 minutes before train P. Find the distance between stations A and B \n" ); document.write( "
Algebra.Com's Answer #539116 by ankor@dixie-net.com(22740)\"\" \"About 
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Two trains P and Q are traveling from station A to station B at speeds of 100kmph and 120 kmph respectively.
\n" ); document.write( " Train Q stops at station C for 10 minutes but reaches station B 5 minutes before train P.
\n" ); document.write( " Find the distance between stations A and B
\n" ); document.write( ":
\n" ); document.write( "Let d = dist from A to B
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\n" ); document.write( "change 10 min to \"1%2F6\" hr, Q's stop at C
\n" ); document.write( "change 5 min to \"1%2F12\" hr, difference in their transit times
\n" ); document.write( ";
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "P's transmit time - Q's transit time = 5 min
\n" ); document.write( "\"d%2F100\" - (\"d%2F120+%2B+1%2F6\") = \"1%2F12\"
\n" ); document.write( "\"d%2F100\" - \"d%2F120\" - \"1%2F6\" = \"1%2F12\"
\n" ); document.write( "Multiply by 600 to cancel the denominators, results:
\n" ); document.write( "6d - 5d - 100 = 50
\n" ); document.write( "d = 50 + 100
\n" ); document.write( "d = 150 km from A to B
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