document.write( "Question 890643: When solving the system of equations by graphing first each equation how do we solve this problem?
\n" ); document.write( "Equations:
\n" ); document.write( "3x+3y=12
\n" ); document.write( "y=-x-4
\n" ); document.write( "when trying to find out what type of solution do we make a output input table for both equations? please solve equation and graph and show me how you did it! \n" ); document.write( "

Algebra.Com's Answer #539112 by fcabanski(1391) $\"\"$ $\"About$

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Both of these equations are for straight lines. Any equation of the form ax + by = c (standard form) or y=mx+b (slope intercept form) is an equation of a straight line. To graph a line, find two points. Connect them.

\n" ); document.write( "The graph will show the solution for this equation as the point(s) where the lines intersect.

\n" ); document.write( "The easiest points to find are the intercepts. What is x when y = 0? And what is y when x = 0

\n" ); document.write( "For equation 1: 3x +3(0) =12 ---> 3x=2 ---> x=4 and 3(0)+3y = 12 ---> y=4. The points are (0,4) and (4,0)

\n" ); document.write( "For equation 2: 0 = -x-4 --->x=-4 and y = -(0) -4 ---> y=-4. The points are (0,-4) and (-4,0)

\n" ); document.write( "In each case, connect the two points. You'll see the two lines are parallel. They never intersect, so this system has no solutions.
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y=4-x%2Cy=+-1x-4+%29\"$ \n" ); document.write( "

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