document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890563>Question 890563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man is 30 years older than his son . in 12 years the man will be 3 times older than his son .find their present age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #539086 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=539086\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> M = S + 30<BR>\n" );
document.write( "M + 12 = 3(S + 12)<BR>\n" );
document.write( "Substitute the value of M from the first equation into the second.<BR>\n" );
document.write( "M + 12 = 3(S+12)<BR>\n" );
document.write( "(S+30) + 12 = 3(S+12)<BR>\n" );
document.write( "Distribute/Add<BR>\n" );
document.write( "S + 42 = 3S + 36<BR>\n" );
document.write( "Subtract S from each side<BR>\n" );
document.write( "42 = 2S + 36<BR>\n" );
document.write( "Subtract 36 from each side<BR>\n" );
document.write( "6 = 2S<BR>\n" );
document.write( "Divide each side by 2<BR>\n" );
document.write( "3 = S<BR>\n" );
document.write( "The son is 3, therefore the man is 33<BR>\n" );
document.write( "In 12 years, the son will be 15, and the man will be 45 -- 3x the son's age. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );