document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890567>Question 890567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of rectangular garden is 5 meters more than its width.If the perimeter is 130 meters,find its dimensions\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #539085 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=539085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is a fence around.  It's 2 widths + 2 lengths.<BR>\n" );
document.write( "130 = 2(L) + 2(W)<BR>\n" );
document.write( "L = W+5<BR>\n" );
document.write( "Substitute the value of L from the bottom equation into the top.<BR>\n" );
document.write( "130 = 2(W+5) + 2W<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "130 = 2W + 10 + 2W<BR>\n" );
document.write( "130 = 4W + 10<BR>\n" );
document.write( "Subtract 10 from each side<BR>\n" );
document.write( "120 = 4W<BR>\n" );
document.write( "Divide each side by 4<BR>\n" );
document.write( "30 = W<BR>\n" );
document.write( "If the width is 30, then the length is 35<BR>\n" );
document.write( "30 + 30 + 35 + 35 = 130 </SPAN>\n" );
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