document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890577>Question 890577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of two numbers is 88. Algebraically determine the numbers if one number is 3 more than the other. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #539084 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=539084\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8 and 11<BR>\n" );
document.write( "The way I did it was finding the factors of 88 (A * B = 88) and then looking at which pair fit the equation A = B + 3<BR>\n" );
document.write( "Well, sort of.  Honestly, this is a 2+2=4 question... </SPAN>\n" );
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