document.write( "Question 890540: two cyclist are 25 mi apart and traveling toward each other.
\n" ); document.write( "One cyclist is traveling at 2/3 the rate of the other.They pass in 2h.Find rate
\n" ); document.write( "of each cyclist. \n" ); document.write( "

Algebra.Com's Answer #539053 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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two cyclist are 25 mi apart and traveling toward each other.
\n" ); document.write( "One cyclist is traveling at 2/3 the rate of the other.
\n" ); document.write( "They pass in 2h.Find rate of each cyclist.
\n" ); document.write( ":
\n" ); document.write( "Let s = the speed of the faster cyclist
\n" ); document.write( "then
\n" ); document.write( " $\"2%2F3\"$ s = the speed of the slower
\n" ); document.write( ":
\n" ); document.write( "Since they are going towards each other, we can solve this by adding their speeds
\n" ); document.write( "1s + $\"2%2F3\"$ s = $\"5%2F3\"$ s, the combined speed of the two bikes
\n" ); document.write( ":
\n" ); document.write( "dist = time * speed
\n" ); document.write( ":
\n" ); document.write( " 2* $\"5%2F3\"$ s = 25
\n" ); document.write( " $\"10%2F3\"$ s = 25
\n" ); document.write( "multiply both sides by 3
\n" ); document.write( "10s = 75
\n" ); document.write( "s = 75/10
\n" ); document.write( "s = 7.5 mph, speed of the faster
\n" ); document.write( "then
\n" ); document.write( " $\"2%2F3\"$ *7.5 = 5 mph the speed of the slower
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this find the distance each traveled
\n" ); document.write( "2*7.5 = 15 mi
\n" ); document.write( "2 * 5 = 10 mi
\n" ); document.write( "----------------
\n" ); document.write( "total dist: 25 mi \n" ); document.write( "

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