document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890375>Question 890375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 76. the second side is twice as long as the first side. The third side is four centimeters shorter than the second side. How long is each side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538975 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538975\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A + B + C = 76 [remember, a perimeter is just a fence around]<BR>\n" );
document.write( "B = 2A<BR>\n" );
document.write( "C = B-4<BR>\n" );
document.write( "Substitute the known values of B & C into the top equation<BR>\n" );
document.write( "A + B + C = 76<BR>\n" );
document.write( "A + 2A + (B-4) = 76<BR>\n" );
document.write( "Substitute again for B<BR>\n" );
document.write( "3A + 2A - 4 = 76<BR>\n" );
document.write( "5A - 4 = 76<BR>\n" );
document.write( "Add 4 to each side<BR>\n" );
document.write( "5A = 80<BR>\n" );
document.write( "Divide each side by 5<BR>\n" );
document.write( "A = 16<BR>\n" );
document.write( "Therefore B = 32, and C = 28<BR>\n" );
document.write( "Sides are 16, 32, and 28 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );