document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890431>Question 890431</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that the sum of the second and the third is equal to four times the first. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538967 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> B = A-2 (they are consecutive odd, so 2 apart)<BR>\n" );
document.write( "C = A-4<BR>\n" );
document.write( "B+C = 4A<BR>\n" );
document.write( "Substitute the known values of B & C from the top equations into the bottom equation.<BR>\n" );
document.write( "B+C = 4A<BR>\n" );
document.write( "(a-2) + (a-4) = 4A<BR>\n" );
document.write( "2A - 6 = 4A<BR>\n" );
document.write( "Subtract 2A from each side<BR>\n" );
document.write( "-6 = 2A<BR>\n" );
document.write( "Divide each side by 2<BR>\n" );
document.write( "-3 = A<BR>\n" );
document.write( "Therefore, B = -5 and C = -7<BR>\n" );
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