document.write( "Question 890301: Jay jay rode his bicycle against the wind for 1 hour and traveled 15 km. then he traveled back the same distance with the wind in 36 minutes, what was the rate of the wind? \n" ); document.write( "
| Algebra.Com's Answer #538954 by ankor@dixie-net.com(22740)     You can put this solution on YOUR website! Jay jay rode his bicycle against the wind for 1 hour and traveled 15 km. \n" ); document.write( " then he traveled back the same distance with the wind in 36 minutes, \n" ); document.write( " what was the rate of the wind? \n" ); document.write( ": \n" ); document.write( "Change 36 to hrs, 36/60 = .6 hrs \n" ); document.write( ": \n" ); document.write( "Let b = bike speed in still air \n" ); document.write( "let w = rate of the the wind \n" ); document.write( "then \n" ); document.write( "(b-w) = effective speed against the wind \n" ); document.write( "(b+w) = effective speed with the wind \n" ); document.write( ": \n" ); document.write( "Write a distance equation for each way, dist = time * speed \n" ); document.write( "1(b-w) = 15 \n" ); document.write( "b = w + 15 \n" ); document.write( "and \n" ); document.write( ".6(b+w) = 15 \n" ); document.write( "replace b = (w+15) \n" ); document.write( ".6((w+15)+ w) = 15 \n" ); document.write( ".6(2w+15) = 15 \n" ); document.write( "1.2w + 9 = 15 \n" ); document.write( "1.2w = 15 - 9 \n" ); document.write( "1.2w = 6 \n" ); document.write( "w = 6/1.2 \n" ); document.write( "w = 5 km/h is the wind \n" ); document.write( " \n" ); document.write( " |