document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890369>Question 890369</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The binary operation * is defined by x*y=xy-y-x for all real values of x and y. If x*3=2*x, find x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538945 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We seem to need to assume, \"-\" means minus, and ab means a multiplied by b.\r<BR>\n" );
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document.write( "x*3=2*x is given and want to solve for x.\r<BR>\n" );
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document.write( "Left side, (x)(3)-3-x.<BR>\n" );
document.write( "Right side, 2x-x-2.<BR>\n" );
document.write( "Left side must equal right side, ...<BR>\n" );
document.write( "(x)(3)-3-x=2x-x-2<BR>\n" );
document.write( "Combining steps,<BR>\n" );
document.write( "3x-x-3=x-2<BR>\n" );
document.write( "2x-3=x-2<BR>\n" );
document.write( "2x-x-3=x-x-2, just using the additive inverse of x<BR>\n" );
document.write( "x-3=-2<BR>\n" );
document.write( "x=-2+3, used additive inverse of -3<BR>\n" );
document.write( "ANSWER: <b>x=1</b> </SPAN>\n" );
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