document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890344>Question 890344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Confused. Help.<BR>\n" );
document.write( "Use the change-of-base rule to express log[3]12 in terms of common logarithms, in terms of natural logarithms, and correct to four decimal places. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538923 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the change of base logarithm rule is<BR>\n" );
document.write( "log (base a) of x = log (base b) of x / log (base b) of a<BR>\n" );
document.write( "1.  common logarithms ( this is base 10)<BR>\n" );
document.write( "log base 3 of 12 = log (base 10) of 12 / log (base 10) of 3 =  1.079181246 /  0.47712125472 = 2.261859507 = 2.2619<BR>\n" );
document.write( "2. natural logarithm ( this is base e)<BR>\n" );
document.write( "log base 3 of 12 = log (base e) of 12 / log (base e) of 3 =  2.4849066498 /  1.0986122887 = 2.261859507 = 2.2619<BR>\n" );
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