document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890366>Question 890366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diameters of the outer and inner shells of a semi circular right prism are 30m and 28m respectively. The lenght of the prism is 120m<BR>\n" );
document.write( "1.Determine the area of the base in terms of pie </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538915 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameters of the outer and inner shells of a semi circular right prism are 30m and 28m respectively. The lenght of the prism is 120m<BR>\n" );
document.write( "1.Determine the area of the base in terms of pie<BR>\n" );
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document.write( "r = 15 and 14<BR>\n" );
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document.write( "For a semi-circle, area = pi*r^2/2  (Notice it's the Greek letter pi, not the dessert, pie)<BR>\n" );
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document.write( "Area = pi*15^2 - pi*14^2 = 29pi sq meters<BR>\n" );
document.write( "That's the area of the semi-circular base.<BR>\n" );
document.write( "The length is not a factor. </SPAN>\n" );
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