document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890306>Question 890306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,<BR>\n" );
document.write( "Please tell me the solution of this:\r<BR>\n" );
document.write( "\n" );
document.write( "Q1)4 cards are drawn at random from a pack of cards then find the probability that <BR>\n" );
document.write( "i)One card is from each suit<BR>\n" );
document.write( "ii)All 4 are picture cards ( a king, a queen, a jack, an ace)\r<BR>\n" );
document.write( "\n" );
document.write( "Regards<BR>\n" );
document.write( "Gargi </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538882 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Both problems involve drawing cards without replacement.<BR>\n" );
document.write( "i.  Probability that one card is from each suit is<BR>\n" );
document.write( "(note that there are 13 cards in each suit)<BR>\n" );
document.write( "13/52 * 13/51 * 13/50 * 13/49 = 0.004395758<BR>\n" );
document.write( "ii.  Probability that all 4 are picture cards is<BR>\n" );
document.write( "(note that there are 4 aces, 4 kings, 4 queens, 4 jacks)<BR>\n" );
document.write( "4/52 * 4/51 * 4/50 * 4/49 = 0.0000394\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );