document.write( "Question 890221: A rectangular garden has an area of 10 square feet. Four less than the width is equal to 23 less than twice the length. \r
\n" ); document.write( "\n" ); document.write( "a) Define variables
\n" ); document.write( "b) Write an equation, in standard form, that models the situation.
\n" ); document.write( "c) Solve your quadratic equation to find the length and the width.
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Algebra.Com's Answer #538839 by josgarithmetic(39617)\"\" \"About 
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w for width and L for length:
\n" ); document.write( "-4+w=-23+2L from the second sentence description.
\n" ); document.write( "That gives \"w-2L=4-23\",
\n" ); document.write( "\"w-2L=-19\"
\n" ); document.write( "\"2L-w=19\".\r
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\n" ); document.write( "\n" ); document.write( "Area description means \"wL=10\".
\n" ); document.write( "Choose either w or L and substitute for it in the area equation. Maybe w is most convenient to use. w=2L-19.
\n" ); document.write( "\"highlight%28%282L-19%29L=10%29\", when substituted.\r
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\n" ); document.write( "\n" ); document.write( "Standard form for the equation is not really the best way to go. Just try simplifying, and if possible, factoring.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%282L%5E2-19L-10=0%29\", general form.
\n" ); document.write( "Discriminant? 19^2-4*2(-10)=19^2+80=441=21^2.
\n" ); document.write( "Directly using general solution of a quadratic equation and the values from the equation,
\n" ); document.write( "\"L=%2819%2B-+21%29%2F4\" MUST be only \"highlight%28L=%2819%2B21%29%2F4=10%29\".\r
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\n" ); document.write( "\n" ); document.write( "Use this in formula for w to find w.
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