document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890227>Question 890227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider the following system of equations.  <BR>\n" );
document.write( "ax+by=1+a<BR>\n" );
document.write( "3ax+2by=-2+b\r<BR>\n" );
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document.write( " If the solution to the above system is (– 1, 3), find the values a and b. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538799 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> plug in -1 for x and 3 for y<BR>\n" );
document.write( "-a+3b=1+a<BR>\n" );
document.write( "-2a+3b=1\r<BR>\n" );
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document.write( "-3a+6b=-2+b<BR>\n" );
document.write( "-3a+5b=-2<BR>\n" );
document.write( "-2a+3b=1\r<BR>\n" );
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document.write( "-3,5,-2<BR>\n" );
document.write( "-2,3,1\r<BR>\n" );
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document.write( "determinant = 1<BR>\n" );
document.write( "a= -11/1 = -11<BR>\n" );
document.write( "b = -7/1 = -7\r<BR>\n" );
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document.write( "-3,5,-2<BR>\n" );
document.write( "-2,3,1\r<BR>\n" );
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document.write( "divide row 1 by -3/1<BR>\n" );
document.write( "1,5/-3,-2/-3<BR>\n" );
document.write( "-2,3,1\r<BR>\n" );
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document.write( "add  down (2/1) *row 1 to row 2<BR>\n" );
document.write( "1,5/-3,2/3<BR>\n" );
document.write( "0,1/-3,7/3\r<BR>\n" );
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document.write( "divide row 2 by 1/-3<BR>\n" );
document.write( "1,5/-3,2/3<BR>\n" );
document.write( "0,1,-7\r<BR>\n" );
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document.write( "We now have the value for the last variable.<BR>\n" );
document.write( "We will work our way up and get the other solutions.\r<BR>\n" );
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document.write( "add up  (-5/-3) *row 2 to row 1<BR>\n" );
document.write( "1,0,-11<BR>\n" );
document.write( "0,1,-7\r<BR>\n" );
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document.write( "final<BR>\n" );
document.write( "1,0,-11<BR>\n" );
document.write( "0,1,-7\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );