document.write( "Question 890159: The ages of three brothers, A,B and C, add up to 22. A is 2.5 times older than C. When A was as old as B is today, B is 3 times as old as C. Find their ages. \n" ); document.write( "
Algebra.Com's Answer #538757 by robertb(5830)\"\" \"About 
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A + B + C = 22, and \"A+=+%285%2F2%29C\", from the given.\r
\n" ); document.write( "\n" ); document.write( "Now A - B = difference between the ages of A and B.
\n" ); document.write( "Hence, A - B years ago,\r
\n" ); document.write( "\n" ); document.write( "B - (A - B) = 3[C - (A - B)], from the third sentence.\r
\n" ); document.write( "\n" ); document.write( "==> 2A = B + 3C, after simplifying the last equation.
\n" ); document.write( "==> 5C = B + 3C, after putting in \"A+=+%285%2F2%29C\"
\n" ); document.write( "==> B = 2C
\n" ); document.write( "Then direct substitution gives
\n" ); document.write( "\"%285%2F2%29C+%2B+2C+%2B+C+=+22\"
\n" ); document.write( "==> \"%2811%2F2%29C+=+22\", or
\n" ); document.write( "C = 4 years old,
\n" ); document.write( "==> B = 8 years old, and
\n" ); document.write( "\"+A+=+%285%2F2%294+=+10\" years old
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