document.write( "Question 890159: The ages of three brothers, A,B and C, add up to 22. A is 2.5 times older than C. When A was as old as B is today, B is 3 times as old as C. Find their ages. \n" ); document.write( "
Algebra.Com's Answer #538757 by robertb(5830)![]() ![]() You can put this solution on YOUR website! A + B + C = 22, and \n" ); document.write( "\n" ); document.write( "Now A - B = difference between the ages of A and B. \n" ); document.write( "Hence, A - B years ago,\r \n" ); document.write( "\n" ); document.write( "B - (A - B) = 3[C - (A - B)], from the third sentence.\r \n" ); document.write( "\n" ); document.write( "==> 2A = B + 3C, after simplifying the last equation. \n" ); document.write( "==> 5C = B + 3C, after putting in \n" ); document.write( "==> B = 2C \n" ); document.write( "Then direct substitution gives \n" ); document.write( " \n" ); document.write( "==> \n" ); document.write( "C = 4 years old, \n" ); document.write( "==> B = 8 years old, and \n" ); document.write( " |