document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890143>Question 890143</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two numbers add up to 37. If the smaller number is increased by half of the larger number, the result is 26. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538740 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538740\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = one number<BR>\n" );
document.write( "y = other number\r<BR>\n" );
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document.write( "x + y = 37 {two numbers add up to 37}<BR>\n" );
document.write( "x + 0.5y = 26 {smaller increased by half larger is 26}\r<BR>\n" );
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document.write( "0.5y = 11   {subtracted the two equations, eliminating x}<BR>\n" );
document.write( "y = 22 {divided each side by 0.5}\r<BR>\n" );
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document.write( "x + y = 37 {two numbers add up to 37}<BR>\n" );
document.write( "x + 22 = 37 {substituted 22 for y}<BR>\n" );
document.write( "x = 15 {subtracted 22 from each side}\r<BR>\n" );
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document.write( "The two numbers are 15 and 22<BR>\n" );
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