document.write( "Question 889435: a man is now 5 times as old as his son. Four years ago,the product of their ages was 52.Find their present age? \n" ); document.write( "
Algebra.Com's Answer #538727 by Nigelyul(18) You can put this solution on YOUR website! Let \"M\" be the age of the man \n" ); document.write( "\"S\" be the age of the son\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The possible values would be \n" ); document.write( "A.) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B.) \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since age cannot be negative, the son's only possible age would be 6.\r \n" ); document.write( "\n" ); document.write( "Substitute \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, the man's age is 30 years old and the son's age is 6. \n" ); document.write( " |