document.write( "Question 10124: three consecutive integers are such that the first plus one half the second plus seven less than twice the third is 2101. What are the integers \n" ); document.write( "
Algebra.Com's Answer #5387 by bonster(299)![]() ![]() ![]() You can put this solution on YOUR website! there are 3 consecutive inteters: \n" ); document.write( "#1: x \n" ); document.write( "#2: x+1 \n" ); document.write( "#3: x+2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+ \n" ); document.write( "x+ \n" ); document.write( "2(x+ \n" ); document.write( "2x+x+1+4x+8x-14=4202 \n" ); document.write( "15x-13=4202 \n" ); document.write( "15x=4215 \n" ); document.write( "x= \n" ); document.write( "x=281\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first number is 281. since they are consecutive numbers, the numbers are 281, 282, 283 \n" ); document.write( " |