document.write( "Question 890100: how do I solve this inequality?\r
\n" ); document.write( "\n" ); document.write( "8x-12 > 8/x
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Algebra.Com's Answer #538698 by MathTherapy(10552)\"\" \"About 
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how do I solve this inequality?\r
\n" ); document.write( "\n" ); document.write( "8x-12 > 8/x
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\n" ); document.write( "\"8x+-+12+%3E+8%2Fx\"........\"x+%3C%3E+0\"
\n" ); document.write( "\"8x%5E2+-+12x+%3E+8\" ------ Multiplying both sides be LCD, x
\n" ); document.write( "\"8x%5E2+-+12x+-+8+%3E+0\"
\n" ); document.write( "\"4%282x%5E2+-+3x+-+2%29+%3E+4%280%29\"
\n" ); document.write( "\"2x%5E2+-+3x+-+2+%3E+0\"
\n" ); document.write( "\"%282x+%2B+1%29%28x+-+2%29+%3E+0\"
\n" ); document.write( "2x + 1 = 0 OR x - 2 = 0 ------- Converting inequality to equality
\n" ); document.write( "2x = - 1 OR x = 0 + 2
\n" ); document.write( "\"x+=+-+1%2F2\" OR x = 2
\n" ); document.write( "Critical points are \"-+1%2F2\", \"0\", since \"x+%3C%3E+0\", and \"2\".
\n" ); document.write( "Therefore the four intervals to check are: \"x+%3C+-+1%2F2\", \"-+1%2F2+%3C+x+%3C+0\", \"0+%3C+x+%3C+2\", and \"x+%3E+2\".
\n" ); document.write( "Intervals that satisfy INEQUALITY: \"highlight_green%28highlight_green%28-+1%2F2+%3C+x+%3C+0%29%29\" and \"highlight_green%28highlight_green%28x+%3E+0%29%29\" \n" ); document.write( "
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