document.write( "Question 890100: how do I solve this inequality?\r
\n" ); document.write( "\n" ); document.write( "8x-12 > 8/x
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Algebra.Com's Answer #538693 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
\"8x-12+%3E+8%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "Do NOT multiply each side by x. \r
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\n" ); document.write( "\n" ); document.write( "\"18x-12-8%2Fx%3E0\"
\n" ); document.write( "\"9x-6-4%2Fx%3E0\"
\n" ); document.write( "Bring the first two terms to higher-terms according to denominator x.
\n" ); document.write( "\"%289x%5E2-6x-4%29%2Fx%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "There, you want to use the NUMERATOR to see how it is related to zero; the denominator will not really be relevant, except that the solution for x must EXCLUDE x=0.\r
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\n" ); document.write( "\n" ); document.write( "The important critical points are at x being the zeros of the numerator.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%286%2B-+sqrt%2836%2B4%2A9%2A4%29%29%2F%282%2A9%29\"
\n" ); document.write( "\"x=%286%2B-+sqrt%2836%2B36%2A4%29%29%2F%282%2A9%29\"
\n" ); document.write( "\"x=%286%2B-+6%2Asqrt%285%29%29%2F%286%2A3%29\"
\n" ); document.write( "\"x=1%2F3%2B-+sqrt%285%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "The inequality will be satisfied for \"highlight%28x%3C1%2F3-%281%2F3%29sqrt%285%29%29\" or for \"highlight%28x%3E1%2F3%2B%281%2F3%29sqrt%285%29%29\"----
\n" ); document.write( "The possibility of x=0 will no longer be necessary to consider since it is not within the domain for this inequality.
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