document.write( "Question 890097: 1.) A store sells one type of candy for 4.00 per pound and another type for 10.00 per pound. If the store combines these two candies to produce an 18- pound mixture for 6.00 per pound, how many pound of the more expensive candy are needed? \r
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Algebra.Com's Answer #538691 by josgarithmetic(39618) $\"\"$ $\"About$

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Any question of this type can be understood and handled in the general manner shown here: Mixture: Two-Part, price or cost, both material amounts unknown - http://www.algebra.com/tutors/mixture-price-two-part-both-parts-unknown.lesson?content_action=show_dev\r
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\n" ); document.write( "\n" ); document.write( "If put the actual given numbers into the equations, you would use
\n" ); document.write( " $\"%284u%2B10v%29%2F18=6\"$ and $\"u%2Bv=18\"$ .
\n" ); document.write( "u = how much of the lower cost candy
\n" ); document.write( "v = how much of the higher cost candy\r
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\n" ); document.write( "\n" ); document.write( "The rational equation can be simplified before using:
\n" ); document.write( " $\"%282u%2B5v%29%2F18=3\"$
\n" ); document.write( " $\"highlight_green%282u%2B5v=54%29\"$ \n" ); document.write( "

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