document.write( "Question 890057: How dou you find the domain and their vertical, horizontal or oblique asymptote?\r
\n" ); document.write( "\n" ); document.write( "r(x) = x^2+x-72/ x^2-x-56
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Algebra.Com's Answer #538683 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
r(x) = x^2+x-72/ x^2-x-56\r
\n" ); document.write( "\n" ); document.write( "The correct text form you want is r(x)=(x^2+x-72)/(x^2-x-56)\r
\n" ); document.write( "\n" ); document.write( "and as rendered looks like \"r%28x%29=%28x%5E2%2Bx-72%29%2F%28x%5E2-x-56%29\"\r
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\n" ); document.write( "\n" ); document.write( "Factor if you can.
\n" ); document.write( "\"r%28x%29=%28%28x-8%29%28x%2B9%29%29%2F%28%28x%2B7%29%28x-8%29%29\".
\n" ); document.write( "A discontinuity occurs at x=8. This is because of the factor \"%28x-8%29%2F%28x-8%29\".
\n" ); document.write( "A vertical asymptote will occur at x=-7 because the function is undefined there.\r
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\n" ); document.write( "\n" ); document.write( "Domain: \"-infinity%3Cx%3C-7\" U \"-7%3Cx%3C8\" U \"8%3Cx%3Cinfinity\".\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-15%2C10%2C-15%2C10%2C%28x%5E2%2Bx-72%29%2F%28x%5E2-x-56%29%29\"\r
\n" ); document.write( "\n" ); document.write( "The graph will not display properly the discontinuity at x=8 but it is there. The HORIZONTAL asymptote is y=1. This might be easier to understand if you take your original function before factoring and examine what happens for x extremely large or small without bound. The x^2 terms in numerator and denominator become increasingly far more important, so each approaches the same square value, and you have the ratio of these.
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