document.write( "Question 890057: How dou you find the domain and their vertical, horizontal or oblique asymptote?\r
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document.write( "r(x) = x^2+x-72/ x^2-x-56 \n" );
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Algebra.Com's Answer #538683 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! r(x) = x^2+x-72/ x^2-x-56\r \n" ); document.write( "\n" ); document.write( "The correct text form you want is r(x)=(x^2+x-72)/(x^2-x-56)\r \n" ); document.write( "\n" ); document.write( "and as rendered looks like \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factor if you can. \n" ); document.write( " \n" ); document.write( "A discontinuity occurs at x=8. This is because of the factor \n" ); document.write( "A vertical asymptote will occur at x=-7 because the function is undefined there.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Domain: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The graph will not display properly the discontinuity at x=8 but it is there. The HORIZONTAL asymptote is y=1. This might be easier to understand if you take your original function before factoring and examine what happens for x extremely large or small without bound. The x^2 terms in numerator and denominator become increasingly far more important, so each approaches the same square value, and you have the ratio of these. \n" ); document.write( " |