document.write( "Question 890018: Binomial distribution
\n" ); document.write( "suppose that 50% of a population is left handed, find the probability that in a group of 50 individuals:
\n" ); document.write( "a. at most 5 are left handed.
\n" ); document.write( "b. at least 5 are left handed.
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Algebra.Com's Answer #538669 by stanbon(75887)\"\" \"About 
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Binomial distribution
\n" ); document.write( " suppose that 50% of a population is left handed, find the probability that in a group of 50 individuals:
\n" ); document.write( " a. at most 5 are left handed.
\n" ); document.write( "P(0<= x <=5) = binomcdf(50,0.5,5) = 0.000000002105\r
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\n" ); document.write( " b. at least 5 are left handed.
\n" ); document.write( "P(6<= x <=50) = 1 - P(0<= x <=5) = 0.999999....
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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