document.write( "Question 890018: Binomial distribution
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document.write( "suppose that 50% of a population is left handed, find the probability that in a group of 50 individuals:
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document.write( "a. at most 5 are left handed.
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document.write( "b. at least 5 are left handed. \n" );
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Algebra.Com's Answer #538669 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Binomial distribution \n" ); document.write( " suppose that 50% of a population is left handed, find the probability that in a group of 50 individuals: \n" ); document.write( " a. at most 5 are left handed. \n" ); document.write( "P(0<= x <=5) = binomcdf(50,0.5,5) = 0.000000002105\r \n" ); document.write( "\n" ); document.write( "----------------------------------- \n" ); document.write( " b. at least 5 are left handed. \n" ); document.write( "P(6<= x <=50) = 1 - P(0<= x <=5) = 0.999999.... \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |