document.write( "Question 10125: jane buys 5 pencils and 2 rubbers for 74 pence and her brother alan buys 2 pencils and one rubber for 31 pence. if each pencil costs x and each rubber costs y , write down a pair of simultaneous equations and solve them to find the cost of the pencil and rubber.\r
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document.write( "5x+2y=74 \n" );
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Algebra.Com's Answer #5386 by bonster(299)![]() ![]() ![]() You can put this solution on YOUR website! each pencil =x \n" ); document.write( "each rubber=y\r \n" ); document.write( "\n" ); document.write( "jane has 5 pencils=5x and 2 rubbers=2y; total pence=74 \n" ); document.write( "alan has 2 pencils=2x and 1 rubber=1y; total pence=31\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x+2y=74 \n" ); document.write( "-2(2x+1y=31) <--multiply by -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x+2y=74 \n" ); document.write( "-4x-2y=-62\r \n" ); document.write( "\n" ); document.write( "x=12\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-2(5x+2y=74) \n" ); document.write( "5(2x+1y=31) \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-10x-4y=-148 \n" ); document.write( "10x+5y=155\r \n" ); document.write( "\n" ); document.write( "y=7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a pencil costs 12 pence and a rubber costs 7 pence \n" ); document.write( " |