document.write( "Question 889725: Alvin is now 20 years older than his son. In 10 years, he will be twice as old as his son's age. What are their present age? \n" ); document.write( "
Algebra.Com's Answer #538589 by Fombitz(32388)\"\" \"About 
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1.\"A=S%2B20\"
\n" ); document.write( "In ten years,
\n" ); document.write( "\"A%2B10=2%28S%2B10%29\"
\n" ); document.write( "\"A%2B10=2S%2B20\"
\n" ); document.write( "2.\"A-2S=10\"
\n" ); document.write( "Substituting from eq. 1,
\n" ); document.write( "\"%28S%2B20%29-2S=10\"
\n" ); document.write( "\"-S%2B20=10\"
\n" ); document.write( "\"-S=-10\"
\n" ); document.write( "\"S=10\"
\n" ); document.write( "Then,
\n" ); document.write( "\"A=10%2B20\"
\n" ); document.write( "\"A=30\"\r
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