document.write( "Question 74972: Please help me with this problem. Thank you!!
\n" ); document.write( "2t^2+7t=4
\n" ); document.write( "Thank you!!! \n" ); document.write( "

Algebra.Com's Answer #53857 by funmath(2933) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"2t%5E2%2B7t=4\"$ set = to 0
\n" ); document.write( " $\"2t%5E2%2B7t-4=4-4\"$
\n" ); document.write( " $\"2t%5E2%2B7t-4=0\"$ Factor however you know how, I'm using grouping or ac method.
\n" ); document.write( "2t^2+__t ___t-4=0
\n" ); document.write( "Fill in the blanks with two numbers that multiply to give you the product of the first and last coefficients (2*-4=-8), but add to give you the middle coefficient (7). 8*-1=-8 and 8+(-1)=7
\n" ); document.write( " $\"2t%5E2%2B8t-1t-4=0\"$ Factor the GCF out of the first two terms and the last two terms:
\n" ); document.write( " $\"2t%28t%2B4%29-1%28t%2B4%29=0\"$ factor out (t+4)
\n" ); document.write( " $\"%28t%2B4%29%282t-1%29=0\"$ set each parentheses=0 and solve for t.
\n" ); document.write( "t+4=0 or 2t-1=0
\n" ); document.write( "t+4-4=0-4 or 2t-1+1=0+1
\n" ); document.write( "t=-4 or 2t=1
\n" ); document.write( "t=-4 or 2t/2=1/2
\n" ); document.write( "t=-4 or t=1/2
\n" ); document.write( "Check by letting t=-4 and t=1/2 and see if both sides equal.
\n" ); document.write( "for t=-4
\n" ); document.write( " $\"2%28-4%29%5E2%2B7%28-4%29=4\"$
\n" ); document.write( " $\"2%2816%29-28=4\"$
\n" ); document.write( " $\"32-28=4\"$
\n" ); document.write( " $\"4=4\"$ This one works.
\n" ); document.write( "for t=1/2
\n" ); document.write( " $\"2%281%2F2%29%5E2%2B7%281%2F2%29=4\"$
\n" ); document.write( " $\"2%281%2F4%29%2B7%281%2F2%29=4\"$
\n" ); document.write( " $\"2%2F4%2B7%2F2=4\"$
\n" ); document.write( " $\"1%2F2%2B7%2F2=4\"$
\n" ); document.write( " $\"%281%2B7%29%2F2=4\"$
\n" ); document.write( " $\"8%2F2=4\"$
\n" ); document.write( " $\"4=4\"$ This one works too.
\n" ); document.write( "Happy Calculating!!!! \n" ); document.write( "

\n" );