document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889953>Question 889953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me by simlifying the following logarithum function.\r<BR>\n" );
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document.write( "log(log(1-x^2)/log(log(cosx). In fact I need to simplify it to find the limit of the above function when xtenda to Zero.\r<BR>\n" );
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document.write( "Regards,\r<BR>\n" );
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document.write( "S B Roy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538562 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538562\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> as x approaches 0, we have<BR>\n" );
document.write( "log(log(1-x^2)/log(log(cosx) = log(log(1)/log(log(cos0)<BR>\n" );
document.write( "now the log 1 = 0 and cos(0) = 1<BR>\n" );
document.write( "we now have<BR>\n" );
document.write( "log(0) / log(1) = -infinity / 0<BR>\n" );
document.write( "note that division by 0 is undefined, therefore this limit is undefined\r<BR>\n" );
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document.write( " </SPAN>\n" );
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