document.write( "Question 889941: could you explain to me please if f(x)=4^x, then f(x+1)-f(x) equals? \n" ); document.write( "

Algebra.Com's Answer #538553 by Edwin McCravy(20060) $\"\"$ $\"About$

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f(x)=4^x, then f(x+1)-f(x)=?
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document.write( "f(x+1) means to start with      f(x)=4^x\r\n" );
document.write( "Put parentheses around the x    f(x)=4^(x)\r\n" );
document.write( "            Take out the x      f( )=4^( )\r\n" );
document.write( "Spread the parentheses wide   f(   )=4^(   )\r\n" );
document.write( "            put in (x+1)      f(x+1)=4^(x+1)\r\n" );
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document.write( "Now take f(x+1)-f(x) and put 4^(x+1) in place of f(x+1)\r\n" );
document.write( "and put 4^x in place of f(x) and you get\r\n" );
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document.write( "         f(x+1)-f(x)=4^(x+1)-4^x\r\n" );
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document.write( "Then you write 4^(x+1) as 4^x*4^1 then as 4^x*4 then as 4*4^x\r\n" );
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document.write( "         f(x+1)-f(x)=4*4^x-4^x\r\n" );
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document.write( "Then factor out 4^x\r\n" );
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document.write( "         f(x+1)-f(x)=4^x(4-1)\r\n" );
document.write( "         f(x+1)-f(x)=4^x(3)\r\n" );
document.write( "         f(x+1)-f(x)=3*4^x\r\n" );
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document.write( "Edwin

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