document.write( "Question 889933: Area of a rectangle is 24cm^2 and perimeter is 20c.m. then length of diagonal is- \n" ); document.write( "

Algebra.Com's Answer #538550 by josgarithmetic(39618) $\"\"$ $\"About$

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x and y the dimensions.
\n" ); document.write( "xy=24 and 2x+2y=20, and for diagonal, size is sqrt(x^2+y^2).\r
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\n" ); document.write( "\n" ); document.write( " $\"x%2By=10\"$ from perimeter.
\n" ); document.write( " $\"y=10-x\"$
\n" ); document.write( "-
\n" ); document.write( " $\"x%2810-x%29=24\"$
\n" ); document.write( " $\"10x-x%5E2=24\"$
\n" ); document.write( " $\"-x%5E2%2B10x-24=0\"$
\n" ); document.write( " $\"x%5E2-10x%2B24=0\"$
\n" ); document.write( " $\"x=%2810%2Bsqrt%28100-4%2A24%29%29%2F2\"$
\n" ); document.write( " $\"x=%2810%2B2%29%2F2\"$
\n" ); document.write( " $\"x=6\"$
\n" ); document.write( "-
\n" ); document.write( " $\"y=10-6\"$
\n" ); document.write( " $\"y=4\"$
\n" ); document.write( "-
\n" ); document.write( "Diagonal is $\"highlight%28sqrt%286%5E2%2B4%5E2%29=sqrt%2852%29=highlight%282sqrt%2813%29%29%29\"$ \n" ); document.write( "

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