document.write( "Question 74968: Science and medicine. A pharmacist wishes to prepare 150 mL of a 20% alcohol
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Algebra.Com's Answer #53851 by psbhowmick(878)\"\" \"About 
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Let us suppose that 'x' ml of 30% alcohol be mixed with 'y' ml of 15% alcohol to form 150 ml of 20% alcohol.\r
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\n" ); document.write( "\n" ); document.write( "150 ml of 20% alcohol consists \"20%2A150%2F100\" = 30 ml of alcohol and (150 - 30) = 120 ml of water.\r
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\n" ); document.write( "\n" ); document.write( "Similarly, 'x' ml of 30% alcohol contains \"30%2Ax%2F100\" = 0.3x ml and (x - 0.3x) = 0.7x ml of water.
\n" ); document.write( "Also, 'y' ml of 30% alcohol contains \"15%2Ay%2F100\" = 0.15y ml and (y - 0.15y) = 0.85y ml of water.\r
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\n" ); document.write( "\n" ); document.write( "Thus total volume of alcohol in final mixture = (0.3x + 0.15y) ml and total volume of water in final mixture = (0.7x + 0.85y) ml.\r
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\n" ); document.write( "\n" ); document.write( "But final mixture contains 30 ml alcohol and 120 ml water.\r
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\n" ); document.write( "\n" ); document.write( "So, \"0.3x+%2B+0.15y+=+30\"______________(1)
\n" ); document.write( "and \"0.7x+%2B+0.85y+=+120\"______________(2)\r
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\n" ); document.write( "\n" ); document.write( "Multiplying (1) by 7 and (2) by 3 and subtracting (1) from (2)
\n" ); document.write( "\"2.55y+-+0.85y+=+360+-+210\"
\n" ); document.write( "\"1.7y+=+170\"
\n" ); document.write( "\"y+=+170%2F1.7+=+100\"\r
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\n" ); document.write( "\n" ); document.write( "So, \"0.3x+%2B+0.15%2A100+=+30\" [from (1)]
\n" ); document.write( "\"0.3x+%2B+15+=+30\"
\n" ); document.write( "\"0.3x+=+30+-+15+=+15\"
\n" ); document.write( "\"x+=+15%2F0.3+=+50\"\r
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\n" ); document.write( "\n" ); document.write( "Hence, 50 ml of 30% alcohol should be mixed with 100 ml of 15% alcohol.
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