document.write( "Question 889855: Moya has a total of $3.10 in her pocket in only 10 and 20 cent coins. If she has 19 coins altogether, how many of each coin does she have? \r
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Algebra.Com's Answer #538507 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = number of 10 cent coins she has
\n" ); document.write( "Let \"+b+\" = number of 20 cent coins she has
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\n" ); document.write( "(1) \"+10a+%2B+20b+=+310+\"
\n" ); document.write( "(2) \"+a+%2B+b+=+19+\"
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\n" ); document.write( "Multiply both sides of (2) by \"+10+\"
\n" ); document.write( "and subtract (2) from (1)
\n" ); document.write( "(1) \"+10a+%2B+20b+=+310+\"
\n" ); document.write( "(2) \"+-10a+-+10b+=+-190+\"
\n" ); document.write( "\"+10b+=+120+\"
\n" ); document.write( "\"+b+=+12+\"
\n" ); document.write( "and, since
\n" ); document.write( "(2) \"+a+%2B+12+=+19+\"
\n" ); document.write( "(2) \"+a+=+7+\"
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\n" ); document.write( "She has 7 of the 10 cent coins
\n" ); document.write( "She has 12 of the 20 cent coins\r
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