document.write( "Question 889870: A plane can fly 310 mph in still air. If it can fly 180 miles downwind in the same amount of time it can fly 130 miles upwind, find the velocity of the wind. \n" ); document.write( "
Algebra.Com's Answer #538497 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A plane can fly 310 mph in still air. If it can fly 180 miles downwind in the same amount of time it can fly 130 miles upwind, find the velocity of the wind. \n" ); document.write( "---------- \n" ); document.write( "Downwid DATA: \n" ); document.write( "distance = 180 miles ; rate = (310+w) mph ; time = 180/(310+w) hrs \n" ); document.write( "---------- \n" ); document.write( "Upwind DATA: \n" ); document.write( "distance = 130 miles ; rate = (310-w) mph ; time = 130/(310-w) hrs \n" ); document.write( "-------------------- \n" ); document.write( "Equation: \n" ); document.write( "time up = time down \n" ); document.write( "130/(310-w) = 180/(310+w) \n" ); document.write( "-------- \n" ); document.write( "130(310+w) = 180(310-w) \n" ); document.write( "13*310 + 13w = 18*310 - 18w \n" ); document.write( "----- \n" ); document.write( "31w = 5*310 \n" ); document.write( "w = 5*10 = 50 mph (rate of the wind) \n" ); document.write( "----------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------ \n" ); document.write( " \n" ); document.write( " |