document.write( "Question 889787: A sum of money is to be distributed among A, B,C and D in the proportion of 5:2:4:3. If C gets Nu. 1000 more than D, what is B's share? \n" ); document.write( "
Algebra.Com's Answer #538472 by ankor@dixie-net.com(22740)\"\" \"About 
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A sum of money is to be distributed among A, B,C and D in the proportion of 5:2:4:3.
\n" ); document.write( "Let x = the multiplier
\n" ); document.write( "then A,B,C,D can be written
\n" ); document.write( "5x, 2x, 4x, 3x
\n" ); document.write( ":
\n" ); document.write( " If C gets Nu. 1000 more than D,
\n" ); document.write( "C = D + 1000
\n" ); document.write( "therefore
\n" ); document.write( "4x = 3x + 1000
\n" ); document.write( "4x - 3x = 1000
\n" ); document.write( "x = 1000 is the multiplier
\n" ); document.write( ":
\n" ); document.write( " what is B's share?
\n" ); document.write( "B = 2x
\n" ); document.write( "B = 2*1000
\n" ); document.write( "B = $2000 \n" ); document.write( "
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