document.write( "Question 74942This question is from textbook Alegbra & Trig w/Geometry
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document.write( ": Find the solution to the equation: 6x – 3 = –2x + 21.\r
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document.write( "Find the solutions to the equation: x2 + 2x – 8 = 0.\r
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document.write( "Find the solutions to the equation: x-5/x = 4.\r
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document.write( "Solve the inequality 21/15-3x<0, and express the solution as an interval. \n" );
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Algebra.Com's Answer #53847 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Find the solution to the equation: 6x – 3 = –2x + 21. \n" ); document.write( "6x+2x-3=-2x+2x+21 \n" ); document.write( "8x-3=21 \n" ); document.write( "8x-3+3=21+3 \n" ); document.write( "8x=24 \n" ); document.write( "8x/8=24/8 \n" ); document.write( " \n" ); document.write( "Check by letting x=3 and see if both sides equal. \n" ); document.write( "6(3)-3=-2(3)+21 \n" ); document.write( "18-3=-6+21 \n" ); document.write( "15=15 We're right!!!! \n" ); document.write( ": \n" ); document.write( "Find the solutions to the equation: x2 + 2x – 8 = 0. \n" ); document.write( "Factor: \n" ); document.write( "x^2+2x-8=0 \n" ); document.write( "(x___)(x___)=0 \n" ); document.write( "Fill the blanks with two numbers that multiply to give you -8, but add to give you 2. 4*-2=-8 and 4-2=2 \n" ); document.write( "(x+4)(x-2)=0 Set each parentheses equal to 0 and solve for x. \n" ); document.write( "x+4=0 or x-2=0 \n" ); document.write( "x+4-4=0-4 or x-2+2=0+2 \n" ); document.write( " \n" ); document.write( "Once again, you can check your solutions by subtituting into the original equation and see if you get 0. \n" ); document.write( "(-4)^2+2(-4)-8=0 \n" ); document.write( "16-8-8=0 \n" ); document.write( "0=0 This one's right. \n" ); document.write( "(2)^2+2(2)-8=0 \n" ); document.write( "4+4-8=0 \n" ); document.write( "0=0 We're right again!!! \n" ); document.write( ": \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "Find the solutions to the equation: x-5/x = 4. \n" ); document.write( "I'm not sure where your fraction begins and ends. I'm going with the way that you typed it. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(x___)(x___)=0 \n" ); document.write( "Fill the blanks with two numbers that multiply to give you -5, but add to give you -4. -5*1=-5 and -5+1=-4 \n" ); document.write( "(x-5)(x+1)=0 set each factor =0 and solve for x \n" ); document.write( "x-5=0 or x+1=0 \n" ); document.write( "x-5+5=0+5 or x+1-1=0-1 \n" ); document.write( " \n" ); document.write( "Check by substitution: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Solve the inequality 21/15-3x<0, and express the solution as an interval. \n" ); document.write( "This one is another one that I'm not sure about where your fraction's denominator begins or ends. I'm going with the way you typed it. If the -3x is part of the denominator let me know. \n" ); document.write( " \n" ); document.write( "Let the denominator =0 to find the critical number. \n" ); document.write( "15-3x=0 \n" ); document.write( "-15+15-3x=0-15 \n" ); document.write( "-3x=-15 \n" ); document.write( "-3x/-3=-15/-3 \n" ); document.write( "x=5 \n" ); document.write( "The intervals to test are (-infinity,5) and (5,infinity) \n" ); document.write( "For the interval (-infinity,5), test x=0. \n" ); document.write( "If x=0 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "For the interval (5,infinity), let x=5 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Therefore, the solution is: (5,infinity) \n" ); document.write( "Happy Calculating!!!! \n" ); document.write( " |