document.write( "Question 889807: Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether it's vertex lies above, on or below the x-axis. Y=4x^2-12x+12
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Algebra.Com's Answer #538447 by josgarithmetic(39617) $\"\"$ $\"About$

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If y=0 then $\"4x%5E2-12x%2B12=0\"$
\n" ); document.write( " $\"x%5E2-3x%2B3=0\"$
\n" ); document.write( "zeros are $\"x=%283%2B-+sqrt%289-12%29%29%2F2\"$
\n" ); document.write( " $\"x=%283%2B-+sqrt%28-3%29%29%2F2\"$ NOT a real number.\r
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\n" ); document.write( "\n" ); document.write( "The parabola does not share any points with the x-axis. The vertex is a minimum as found that the coefficient on $\"x%5E2\"$ , 4, is positive; and the vertex is above the x-axis. \n" ); document.write( "

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