document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889740>Question 889740</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length and breadth of a field are 20 m and 10 m respectively. If its length is increased by 20% and breadth<BR>\n" );
document.write( "is decreased by 10%, the new area will be what times of old area?. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538422 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538422\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length and breadth of a field are 20 m and 10 m respectively. If its length is increased by 20% and breadth<BR>\n" );
document.write( "is decreased by 10%, the new area will be what times of old area?.<BR>\n" );
document.write( "length is 20m and breadth is 10 m    area =20x10=200 m^2<BR>\n" );
document.write( "length is increased 20% means new length will be =20x1.2=24 m<BR>\n" );
document.write( "breadth reduced 10% means new breadth will be = 10x0.9=9m<BR>\n" );
document.write( "new area =24x9= 216 m^2 <BR>\n" );
document.write( "new area increased  =216-200/200=8% <BR>\n" );
document.write( "new area increase by 8% answer  <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );