document.write( "Question 889713: two rectangles have an area of 630 cm square each. the difference in the lengths of the rectangle is 5 cm while that in their widths is 3 cm. find the dimension of the two rectangles. \n" ); document.write( "

Algebra.Com's Answer #538384 by lwsshak3(11628) $\"\"$ $\"About$

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two rectangles have an area of 630 cm square each. the difference in the lengths of the rectangle is 5 cm while that in their widths is 3 cm. find the dimension of the two rectangles.
\n" ); document.write( "***
\n" ); document.write( "let x=length of 1st triangle
\n" ); document.write( "let y=width of 1st triangle
\n" ); document.write( "let x-5=length of 2nd triangle
\n" ); document.write( "let y+3=width of 2nd triangle
\n" ); document.write( "..
\n" ); document.write( "length*width=area
\n" ); document.write( "xy=630
\n" ); document.write( "y=630/x
\n" ); document.write( "..
\n" ); document.write( " $\"%28x-5%29%28y%2B3%29=630\"$
\n" ); document.write( " $\"%28x-5%29%28630%2Fx%2B3%29=630\"$
\n" ); document.write( " $\"%28x-5%29%28630%2B3x%29%2Fx=630\"$
\n" ); document.write( " $\"%28x-5%29%283x%2B630%29=630x\"$
\n" ); document.write( " $\"3x%5E2%2B615x-3150=630x\"$
\n" ); document.write( " $\"3x%5E2-15x-3150=0\"$
\n" ); document.write( "x^2-5x-1050=0
\n" ); document.write( "(x+30)(x-35)=0
\n" ); document.write( "x=-30 (reject)
\n" ); document.write( "or
\n" ); document.write( "x=35
\n" ); document.write( "y=630/x=18
\n" ); document.write( "x-5=30
\n" ); document.write( "y+3=21
\n" ); document.write( "..
\n" ); document.write( "dimension of 1st rectangle=35 by 18 cm
\n" ); document.write( "dimension of 2nd rectangle=30 by 21 cm \n" ); document.write( "

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