document.write( "Question 889689: One cement mason can lay a cement foundation in 8 hours, while it takes a second 12 hours to do the same task. After working alone for 4 hours, the fist mason quits. How long will it take the second mason to complete the task?\r
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Algebra.Com's Answer #538359 by josgarithmetic(39616)![]() ![]() ![]() You can put this solution on YOUR website! Uniform Rates of each mason: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Basic uniform rate idea is RT=J rate time job.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let h = time in hours for the second mason to finish after the first mason stops. The two masons do not work simultaneously.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Solve for h. \n" ); document.write( " |