document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889660>Question 889660</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the exact value of  cot(-390º) / sec(22&#960;/3)  Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538348 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538348\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the exact value of cot(-390º) / sec(22&#960;/3) <BR>\n" );
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document.write( "cot(-390) = cot(-30) = -cot(30) = -sqrt(3)<BR>\n" );
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document.write( "sec(22pi/3) = sec((4/3)pi) = sec(240 deg) = -sec(60) = -2<BR>\n" );
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document.write( "Ans: -sqrt(3)/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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