document.write( "Question 889648: Hi
\n" ); document.write( "I really need help with this problem. Use the substitution method to solve
\n" ); document.write( "Y=-2X-4
\n" ); document.write( "3X+Y=1\r
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\n" ); document.write( "\n" ); document.write( "If you can help it will be deeply appreciated. \r
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Algebra.Com's Answer #538318 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Y=-2X-4
\n" ); document.write( "3X+Y=1
\n" ); document.write( "-------------
\n" ); document.write( "y is solved for in the 1st eqn
\n" ); document.write( "Sub -2x-4 for y in the 2nd eqn
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