document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10110>Question 10110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi Free Tutors:\r<BR>\n" );
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document.write( "I am having trouble with the following problme:\r<BR>\n" );
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document.write( "-2[3a-2(4a-1)]+2=2(a+1) on this problem I have tried the following steps\r<BR>\n" );
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document.write( "-6a-8a+2+2=2a+2<BR>\n" );
document.write( "-14a+4=2a+2<BR>\n" );
document.write( "-16a=-2<BR>\n" );
document.write( "a=1/8\r<BR>\n" );
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document.write( "But according to the answer in the back of the book, answer is wrong and I am not sure what I am doing wrong.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5383 by </B><A HREF=/tutors/aboutme.mpl?userid=gina><B>gina(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gina><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2[3a-2(4a-1)]+ 2 = 2(a+1)<BR>\n" );
document.write( "-2[3a-8a+2]+2 = 2a + 1<BR>\n" );
document.write( "3a - 8a + 2 = 2a + 1<BR>\n" );
document.write( "-5a + 2 = 2a + 1<BR>\n" );
document.write( "-5a + 5a + 2 - 1 = 2a + 5a + 1 - 1<BR>\n" );
document.write( "1 = 7a<BR>\n" );
document.write( "1/7 = 7a/7<BR>\n" );
document.write( "1/7 = a\r<BR>\n" );
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