document.write( "Question 889613: A train running at 3 / 7 of its own speed reached the destination in 14 hours, how much time could be saved if the train would have run at its own speed ? \n" ); document.write( "
Algebra.Com's Answer #538293 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! train running at 3 / 7 of its own speed reached the destination in 14 hours, \n" ); document.write( " how much time could be saved if the train would have run at its own speed ? \n" ); document.write( ": \n" ); document.write( "let s = normal speed of the train \n" ); document.write( "let t = time required at normal speed \n" ); document.write( ": \n" ); document.write( "Write a dist equation, dist = speed * time \n" ); document.write( " \n" ); document.write( "multiply both sides by 7 \n" ); document.write( "3s*14 = 7st \n" ); document.write( "divide both sides by s \n" ); document.write( "3*14 = 7t \n" ); document.write( "42 = 7t \n" ); document.write( "t = 42/7 \n" ); document.write( "t = 6 hrs to make the trip at normal speed (they would save 8 hrs) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this using a normal speed of 70, (slow speed = 30) \n" ); document.write( "should be the same dist \n" ); document.write( "30*14 = 420 mi \n" ); document.write( "70*6 = 420 mi \n" ); document.write( " |