document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889554>Question 889554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of A when cos 2A=sin 3A. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538268 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538268\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cos2A = sin3A<BR>\n" );
document.write( "==> cos2A = cos(90 - 3A)<BR>\n" );
document.write( "==> Either 2A = 90 - 3A or 2A = -(90 - 3A)<BR>\n" );
document.write( "==> 5A = 90 or 2A  = -90 +3A<BR>\n" );
document.write( "==> A  = 18 or A = 90.  These are the solutions from 0 degrees to 360 degrees. </SPAN>\n" );
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